25x^2+20cu+4u^2=0

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Solution for 25x^2+20cu+4u^2=0 equation:


Simplifying
25x2 + 20cu + 4u2 = 0

Reorder the terms:
20cu + 4u2 + 25x2 = 0

Solving
20cu + 4u2 + 25x2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4u2' to each side of the equation.
20cu + 4u2 + -4u2 + 25x2 = 0 + -4u2

Combine like terms: 4u2 + -4u2 = 0
20cu + 0 + 25x2 = 0 + -4u2
20cu + 25x2 = 0 + -4u2
Remove the zero:
20cu + 25x2 = -4u2

Add '-25x2' to each side of the equation.
20cu + 25x2 + -25x2 = -4u2 + -25x2

Combine like terms: 25x2 + -25x2 = 0
20cu + 0 = -4u2 + -25x2
20cu = -4u2 + -25x2

Divide each side by '20u'.
c = -0.2u + -1.25u-1x2

Simplifying
c = -0.2u + -1.25u-1x2

Reorder the terms:
c = -1.25u-1x2 + -0.2u

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